Question

find the area of rhombus whose perimeter is 200 meter and one of its angle is 80 metre

Answer 1

in rhombus all sides are equal.
formula of perimeter = 4 x side.
so = 200/4 = 50m.
diagnol = 80m.
in rhombus it can be divided into four equal triangles.

so we can find the area of one of those triangles by pythagoras theorem.

we have hypotenuse (side of the rhombus) = 50m
we have one side = 80/2 = 40m
formula = hypotenues​2 - other side2
=> 502 - 402 = other side 2
=>2500 - 1600 = 9000
root of 9000 = 30 .

we have to find the area of triangle
= 1/2 b x h
= 1/2 x 30 x 40
= 600m
so a rhombus contains 4 equal triangles.
total area of rhombus = 600 x 4= 2400m
therefore 2400m is the area of the rhombus.

hope u like my answer.