Question

find the area of rhombus whose side is of length 5 m and one of its diagonals is of length 8 m​

Answer 1

Answer:

Length of the side of the rhombus = 5 m

Length of the diagonal of the rhombus = 8 m

We know that :-

\tt{The\:diagonals\:of\:rhombus\:bisect\:each\:other\:at\:right\:angles.}Thediagonalsofrhombusbisecteachotheratrightangles.

Due to that property, the half of the other diagonal will be :-

By the Pythagoras Theorem:-

=》 \tt{H^{2} = P^{2} + B^{2}}H2=P2+B2

=》 \tt{5^{2} = 4^{2} + x^{2}}52=42+x2

=》 \tt{25 - 16 = x^{2}}25−16=x2

=》 \tt{9 = x^{2}}9=x2

=》 \tt{x = 3 m}x=3m

Now, that we have the half of the length of the other diagonal, we can say that the length of the diagonal = 3 × 2 (m)

=》 \boxed{\tt{6 m}}6m