Question

In triangle ABC, angle B =90°, AC=16, BC = 8 root 3 . find angle C and angle A.


pls help me quickly....​

Answer 1

cosC = BC/AC = 8√3/16 = √3/2

cosC = cos30°

<C = 30°

<A = 180 - (<B+<C)

= 180 - (90+30) = 180 - 120 = 60°

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