Question

find the area of right angle isosceles triangle whose equal side is 16 cm each​

Answer 1

Answer:128 cm^2

Step-by-step explanation:

Formula is x^2/2

Then x=16

16^2/2. =. 256/2

Hence it will 128 cm^2

Answer 2

Answer:

128cm2

Step-by-step explanation:

In triangle ABC

Angle B = 90°

Angle AB = Angle BC = 16 cm (given)

Area of triangle ABC =1/2 × Base × Height

=1/2 × 16 × 16

= 128cm2