Find the area of right angle triangle whose hypotenuse is 13 and one of its leg is 12 cm long
Answers
Answered by
0
Step-by-step explanation:
(hypotenuse )square= side first square + side second square
169=144+side second square
169-144=side second square
25=side second square
5=side second
area of right angled triangle=1/2* product of first side and second side
area of right angled triangle=1/2*5*12
area of right angled triangle=30sq.cm
I hopes it will helps you❤️❤️
Answered by
2
Hey bro it’s your answer easy explain
169 = 144+ side second square
169–144=side second square
25=second side square
5=side second square
area of right angled triangle = 1/2*5*12
area of right angled triangle= 30sq.cm
Bro it’s the answer but please mark as brainliest pls I don’t have any brainliest answers hope it helps you.
169 = 144+ side second square
169–144=side second square
25=second side square
5=side second square
area of right angled triangle = 1/2*5*12
area of right angled triangle= 30sq.cm
Bro it’s the answer but please mark as brainliest pls I don’t have any brainliest answers hope it helps you.
Similar questions