Math, asked by Anubhavsingh7690, 8 months ago

Find the area of right angle triangle whose hypotenuse is 13 and one of its leg is 12 cm long

Answers

Answered by TheNarayan
0

Step-by-step explanation:

(hypotenuse )square= side first square + side second square

169=144+side second square

169-144=side second square

25=side second square

5=side second

area of right angled triangle=1/2* product of first side and second side

area of right angled triangle=1/2*5*12

area of right angled triangle=30sq.cm

I hopes it will helps you❤️❤️

Answered by Aaravthepro242
2
Hey bro it’s your answer easy explain

169 = 144+ side second square

169–144=side second square

25=second side square

5=side second square

area of right angled triangle = 1/2*5*12

area of right angled triangle= 30sq.cm



Bro it’s the answer but please mark as brainliest pls I don’t have any brainliest answers hope it helps you.
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