Question

Find the area of right angled triangle in which sides other than hypotenuse are 18 cm and 80cm also find the perimeter of the triangle

Answer 1

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Here's your Answer...

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Since, it is a Right Angle Triangle.

By Pythagoras theorem,

H^2 = B^2 + P^2

H^2 = 18^2 + 80^2

H^2 = 324 + 6400

H^2 = 6724

H= 82 cm.

Now, Perimeter of triangle = 80 + 82 + 18

= 180 cm.

Now, Area of Triangle= 1/2 × base × height

= 1/2 × 18 × 80

= 9 × 80

= 720cm^2.

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Answer 2

Area of ∆ = 720 cm^2

Perimeter of∆ = 180 cm

$\bf{Step\:wise\:explanation}$


Sides other than hypotenuse are base and perpendicular.

Given :

Base = 18 cm

Perpendicular= 80 cm

Area of ∆ = 1/2 base ×height

=1/2 ×18×80

=9×80

=720 cm^2

Using PGT -

Hypotenuse^2 = base^2 + perpendicular^2

H^2 = 18^2 +80^2

H^2 = 324 + 6400

H^2 = 6724

H=√6724

H = 82 cm

Perimeter of ∆ = Hypotenuse+ base + perpendicular

= 82 +18+80

= 180 cm