Question

find the area of right angled triangle with length of sides containing the right angle as 8cm and 10cm .​

Answer 1

Answer:

By pythagoras theorem:-

8^2+10^2=(Hypotenuse)^2

64+100=(Hypotenuse)^2

164=(Hypotenuse)^2

root164=Hypotenuse

12.8=Hypotenuse

Area of right angled triangle=1/2(Base×Height)

=1/2(8×10)

=1/2×80

=40cm^2

Answer 2

find the area of right angled triangle with length of sides containing the right angle as 8cm and 10cm .