Question

find the area of right isoscless triangle whose height is 2 and base is 2√2​

Answer 1

Answer:

area of triangle=base×height/2

=2√2×2/2

= 2√2unit square

hope this will help you

Answer 2

Answer:

for a triangle area = $\frac{1}{2}$ × $b$ × $h$

putting the values

$\frac{1}{2}$ × $2$ × $2\sqrt{2}$

area = $2\sqrt{2}$$m^{2}$

Step-by-step explanation: