Question

find the area of sector whose radius is 7cm with the angle
${60}^{0}$

Answer 1

The area of the sector = 25.66 cm²


SOLUTION :-


Given that :-

Radius = 7 cm
Angle at centre = 60 degrees.

To find :- Area of the sector.

So,

Area of sector is equal to :-

$\dfrac{\pi {r}^{2} \alpha }{360}$

Where,

Alpha is the angle at the centre.

So,

Area of given sector is equal to :-

$\dfrac{ \dfrac{22}{7} \times 7 \times 7 \times 60 }{360} \\ \\ = \frac{22 \times 7 \times 6}{36} \\ \\ = \frac{22 \times 7}{6} \\ \\ = \frac{11 \times 7}{3} \\ \\ = \frac{77}{3} = 25.66 \: {cm}^{2}$

Thanks!

Answer 2

Formula :

Area of sector = π r² / 360° × θ

Given information :

r = 7 cm

θ = 60°

Take π as 22 / 7

Finding the area :

So : area = π r² / 360° ×  θ

               = 22 / 7 × ( 7 cm ) × ( 7 cm ) × 60°/360°

               = 22 × 7 cm² × 6

               = 154 / 6 cm²

               = 77/ 3 cm²

               = 25.666666 cm²

$\huge{\underline{\underline{\textsf{ANSWER}}}}}$

25.67  cm²

Hope it helps :-)

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