Question

Find the area
of shaded region

Answer 1

Step-by-step explanation:

its 290cm, the area of the place

Answer 2

Answer:

$\frac{169}{3}$

Step-by-step explanation:

First find area of ∆POQ

$\frac{ \sqrt{3} }{4} \times {10}^{2} \\ = 25 \sqrt{3}$

Area of semicircle PBQ

$\frac{1}{2} \pi {r}^{2} \\ \frac{1}{2} \pi {(5)}^{2} \\ = \frac{25\pi}{2}$

Total area =

$\frac{25\pi}{2} + 25 \sqrt{3 } \\ \frac{25(\pi + 2 \sqrt{3)} }{2}$

Shaded = total - area of sector

area of sector =

$\frac{1}{6} \pi {r}^{2} \\ \frac{1}{6} \pi {(10) }^{2} \\ = \frac{25\pi}{3}$

Shaded is

$\frac{25(\pi + 2 \sqrt{3)} }{2} - \frac{25\pi}{3} \\ = \frac{25(\pi + 6 \sqrt{3) } }{6}$

Put

$\pi = 3.14 \: \: \: \: \\ \sqrt{3 } = 1.73$

Then area =

$\frac{169}{3}$