find the area of shaded region
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Angle of sector= 30°
OB=OA =21cm
OD=OC=7cm
Area of shaded region= 30°/360 πOB²- 30/360πOD²= 30/360π°(OB²-OD²)
1/12π(OB+OD)(OB-OD)
1/12π(21+7)(21-7)
1/12π(28)(14)
1/6π(14)(14)
1/3π(7)(14)
=1/3π(98)
102.66cm²(Approx)
ANS:102.66cm²
OB=OA =21cm
OD=OC=7cm
Area of shaded region= 30°/360 πOB²- 30/360πOD²= 30/360π°(OB²-OD²)
1/12π(OB+OD)(OB-OD)
1/12π(21+7)(21-7)
1/12π(28)(14)
1/6π(14)(14)
1/3π(7)(14)
=1/3π(98)
102.66cm²(Approx)
ANS:102.66cm²
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1
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