Find the area of square inscribed in a circle of radius 8cm?
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Answered by
225
Given,
Radius = r=8cm
∵ The diagonals of square subtend right angle at circumference.
∴The diagonals of square are diameters of circle.
BD = 2*8 = 16cm
Let the sides of square be 'x' cm
in the right angle triangle BCD,
BC² +CD² = BD²
x² + x² = 16²
2x² = 256
x² = 128
Thus the area of square is x² = 128cm²
Radius = r=8cm
∵ The diagonals of square subtend right angle at circumference.
∴The diagonals of square are diameters of circle.
BD = 2*8 = 16cm
Let the sides of square be 'x' cm
in the right angle triangle BCD,
BC² +CD² = BD²
x² + x² = 16²
2x² = 256
x² = 128
Thus the area of square is x² = 128cm²
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Answered by
94
radius =8 cm
dimeter = 2×8 =16
diameter of circle = hypotanous of triangle
Let side be =xcm
using Pythagoras theorem
so ,
x^2+x^2=256
2 x^2=256
x= 128
hence area of square =128 cm ^2
dimeter = 2×8 =16
diameter of circle = hypotanous of triangle
Let side be =xcm
using Pythagoras theorem
so ,
x^2+x^2=256
2 x^2=256
x= 128
hence area of square =128 cm ^2
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