Question

Find the area of square inscribed in a circle of radius 8cm?

Answer 1

Given,

Radius = r=8cm

∵ The diagonals of square subtend right angle at circumference.

∴The diagonals of square are diameters of circle.

BD = 2*8 = 16cm

Let the sides of square be 'x' cm

in the right angle triangle BCD,

BC² +CD² = BD²

x² + x² = 16²

2x² = 256

x² = 128

Thus the area of square is x² = 128cm² 

Answer 2

radius =8 cm
dimeter = 2×8 =16
diameter of circle = hypotanous of triangle
Let side be =xcm
using Pythagoras theorem
so ,
x^2+x^2=256
2 x^2=256
x= 128

hence area of square =128 cm ^2