Math, asked by savi2pptv9BETvijv, 1 year ago

(Root3-1)costheta +(root3+1)sintheta=2 find general solution

Answers

Answered by abhi178
1
let theta =@

now
(root3-1) cos@+(root3+1) sin@=2

root {(root3-1)^2+(root3+1)^2} cos(@-tan^-1(root3+1)/(root3-1)}=2

2root2 cos (@-5pi/12)=2

cos (@-5pi/12)=1/root2=cospi/4

use general solution of cosine
@-5pi/12=2.n.pi+_pi/4

@=2n.pi+_pi/4+5pi/12

where n is integers



Answered by duragpalsingh
1
Please find both the 2 attachments:
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