Question

Find the area of square rhombus with length of diagonals as 8 cm and 14 cm

Answer 1

area of a rhombus =1/2×d1×d2

=1/2×8×14

=56 cm square

Answer 2

$hey \: mate \: here \: is \: your \: answer$

$\textbf{Given That }$

There is a Rhombus who's Length of diagonals are 8 cm and 14 cm . We need to find its Area .


$\textbf{Solution}$

Now To Find Area Of Rhombus Follow This Steps....

Here It's Given That Diagonals Of Rhombus Are 8cm And 14cm

SO LET

First Diagonal (D1) = 8cm

And

Second Diagonal (D2) = 14cm

So Now To Find Area Of Rhombus ...

We Know That Area Of Rhombus Is Equal To ....

$\frac{1}{2}( (d1) \times (d2)) \: \: ( \: where \: d1 \: and \: d2 \: are \: diagnols \: )$


So Now Putting Values Of D1 And D2 In The Formula We Have ....


$\frac{1}{2} \times (8cm \times 14cm)$


That is ➡️


$\frac{1}{2} \times (112 {cm}^{2} )$

This is equal to ➡️

$56 {cm}^{2}$

Therefore Area Of Rhombus is = 56(cm)^2


Hence The Required Answer Is ➡️

$56 {cm}^{2}$


$hope \: its \: help \: full$

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