Find the area of square that can be inscribed in a circle of radius 8cm
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Given radius of the circle is 8 cm.
Therefore, diameter of the circle=(8*2)cm=16cm.
Let the side of the square= a cm
Therefore, diagonal of the square= a*root over of 2cm.
By the condition,
a*root over of 2=16
or, a=16/root over of 2
or, a²=(16/root over of 2)²=16*16/2=128cm².
Hope this is the right answer.
Therefore, diameter of the circle=(8*2)cm=16cm.
Let the side of the square= a cm
Therefore, diagonal of the square= a*root over of 2cm.
By the condition,
a*root over of 2=16
or, a=16/root over of 2
or, a²=(16/root over of 2)²=16*16/2=128cm².
Hope this is the right answer.
Answered by
5
hello users ...
Solution:-
we know that
The length of Diagonal inside a square = a√2 unit
And
Area of square = a²
where, a is the side of square.
Here,
Diagonal of square inscribed inside a circle = r + r = 2r
=> Diagonal = 2 * 8 = 16 cm
=> a√2 = 16 cm
=> a = 16 / √2 = 8√2 cm
Now,
Area = a²
= (8√2)²
= 64 * 2
= 128 cm² Answer
# hope it helps :)
Solution:-
we know that
The length of Diagonal inside a square = a√2 unit
And
Area of square = a²
where, a is the side of square.
Here,
Diagonal of square inscribed inside a circle = r + r = 2r
=> Diagonal = 2 * 8 = 16 cm
=> a√2 = 16 cm
=> a = 16 / √2 = 8√2 cm
Now,
Area = a²
= (8√2)²
= 64 * 2
= 128 cm² Answer
# hope it helps :)
Anonymous:
Hey! May I know.....why u haven't declared Diagonal of the Square as being the dia. of the CIRCUMSCRIBED Circle????
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