Find the area of square whose diagonal is 6cm
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SIDE OF THE SQUARE= A
DIAGONAL= 6CM
HERE WE COULD GET TWO RIGHT ANGLE TRIANGLES
SO A²+A²=6²
2A²=36
A²=36/2
A²=18
THE AREA OF THIS SQUARE IS 18 CM²
DIAGONAL= 6CM
HERE WE COULD GET TWO RIGHT ANGLE TRIANGLES
SO A²+A²=6²
2A²=36
A²=36/2
A²=18
THE AREA OF THIS SQUARE IS 18 CM²
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The area of square is 18 cm².
Given - Diagonal
Find - Area of square
Solution - The diagonal of square and the adjacent two sides will together form the right angled triangle. As all the sides are equal, let us assume the side to be x.
Now, using Pythagoras theorem to find the value of x².
Hypotenuse² = Base² + Perpendicular²
6² = x² + x²
Performing addition on Right Hand Side
36 = 2x²
Shifting 2 to other side of equation and finding the value of x².
Performing Division to find the value of x²
The area of area of square is product of two sides. So, the value calculated above is area of square.
Hence, the area of square is 18 cm².
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