find the area of square whose perimeter is 32
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perimeter of square=32(given)
perimeter =4a
32=4a
a=32/4
a=8( side of square)
area of square=side ×side
=8×8
=64
rhg97:
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Your answer :- ✔✔✔✔✔✔✔
![perimeter \: of \: square \\ = 4 \times side \\ \\ 4 \times side = 32 \\ \\ side = \frac{32}{4} \\ \\ side = 8 \\ \\ area \: of \: square = {side}^{2} \\ \\ = {8}^{2} \\ \\ = 64 perimeter \: of \: square \\ = 4 \times side \\ \\ 4 \times side = 32 \\ \\ side = \frac{32}{4} \\ \\ side = 8 \\ \\ area \: of \: square = {side}^{2} \\ \\ = {8}^{2} \\ \\ = 64](https://tex.z-dn.net/?f=perimeter+%5C%3A+of+%5C%3A+square++%5C%5C+%3D+4+%5Ctimes+side+%5C%5C++%5C%5C+4+%5Ctimes+side+%3D+32+%5C%5C++%5C%5C+side+%3D++%5Cfrac%7B32%7D%7B4%7D++%5C%5C++%5C%5C+side+%3D+8+%5C%5C++%5C%5C+area+%5C%3A+of+%5C%3A+square+%3D++%7Bside%7D%5E%7B2%7D++%5C%5C++%5C%5C++%3D++%7B8%7D%5E%7B2%7D++%5C%5C++%5C%5C++%3D+64+)
Hope it helps
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Your answer :- ✔✔✔✔✔✔✔
Hope it helps
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