Physics, asked by muhammadshahab97, 1 year ago

Solve Numerical correctly and I will mark brainiest. answer is -4ms^-2 and 400m. ​

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Answers

Answered by psychopath69
1

u=40

v=0

t=10

v=u-at

0=40-10a

a=4 deceleration

d1=ut=40×5=200

d2=ut+0.5at^2

=40×10-0.5×4×100

=400-200

=200

total distance=d1 + d2

=400

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