Question

find the area of square whose perimeter is equal to the perimeter of rectangle of size 14 cmby 12 cm​

Answer 1

Answer:

169cm²

Step-by-step explanation:

perimeter of rectangle having length 14cm and breadth 12cm is 2(14+12)cm or 52cm

it is given that perimeter of both rectangle and square are equal

then perimeter of square is 52m

but we know that if a square have side of length x then its perimeter is 4x

then 4x=52

or x= 13cm

then area of the square is x² or 13² cm² =169 cm2

Hope it will help you

Answer 2

☆ Question ☆

Find the area of square whose perimeter is equal to the perimeter of rectangle of size 14 cm by 12 cm.

☆ Solution ☆

Given

• Area of square whose perimeter is equal to the perimeter of rectangle of size 14 cm by 12 cm.

To find

• Area of square

Step-by-Step-Explaination

We know that,

Perimeter of rectangle = 2(l + b)

Perimeter of rectangle = 2(14 + 12)

Perimeter of rectangle = 2 × 26

Perimeter of rectangle = 52 cm

Given, Perimeter of square = Perimeter of rectangle

So, Square perimeter = 52 cm

Now,

Side of square = $\frac{Perimeter\: of\: square}{Number \:of \:sides}$

Side of square = $\frac{52}{4}$

Side of square = 13 cm

We know that

Area of square = $( {side})^{2}$

Area of square = $( {13})^{2}$

Area of square = $169 \: {cm}^{2}$

Thus,

The area of square is $169 \: {cm}^{2}$

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☆ Additional Information ☆

Perimeter of Rectangle = 2( L + B )

Area of Rectangle = L * W

Perimeter of Square = 4 × Side

Area of Square = ${a}^{2}$

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