Question

Find the area of the a ∆, two sides of which are 8cm and 11cm and the perimeter is 32cm.

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Answer 1

$\huge\star\underline\mathfrak\red{Answer:-}$

Perimeter of ∆ = 32cm

a = 8cm

b= 11cm

Third side c = 32cm+(8+11) cm

= 13cm

So, 2s = 32 , i.e., s = 16cm

s-a = (16-8) cm = 8cm

s-b= (16-11) cm = 5cm

s-c = (16-13) cm = 3cm

therefore, area of ∆ = √s(s-a) (s-b) (s-c)

= √16×8×5×3cm^2

= 8√30cm^2

Answer 2

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