Math, asked by Anonymous, 10 months ago

prove that
sinA×secA+cosA×cosecA=secA×cosecA​

Answers

Answered by drjiya123
0

Sin A×1/CosA+Cos A×1/SinA

=Sin A/CosA+Cos A/SinA

=Sin^2A+Cos^2A/SinACosA

=1/SinACosA

=SecA×CosecA

=RHS

Hope it helps

Mark it as BRAINLIEST if you are satisfied with the answer

Answered by Anonymous
1

L.H.S =>

=sinAsecA+cosAcosecA

=sinA/cosA+cosA/sinA

=(sin²A+cos²A)/sinAcosA

=1/sinAcosA

=cosecAsecA

=> R.H.S

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