Question

Find the area of the adjoining heptagon ABCDEFG Fig. (i) in which AC=6.5 cm,BM=32 cm. DN = 4,5 cm, AG= 10 cm and AP=4,4 cm
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Answer 1

Answer:  Area of the heptagon is 91.35.

Step-by-step explanation:  

1. Given data  

 AC = 6.5 cm  

 BM = 3.2 cm  

 CE= PF= 9 cm  

 AG = 10 cm  

 AP = 4.4 cm  

 CP = AC-AP= 6.5 - 4.4= 2.1 cm  

 ND = 4.5 cm

2. Area of heptagon = area of ΔABC +area of trapezium PAGF + area of rectangle PFEC + area of ΔCED     ...1)

 

3. Area of ΔABC =  1/2AC x BM= 10.4       ...2)

 

4. Area of trapezium PAGF = 1/2(PF+AG)x BM= 41.8      ...3)

 

5. Area of rectangle PFEC =CE×PC=9×2.1=18.9     ...4)  

6. Area of ΔCED = 1/2CE x ND= 20.25         ...2)

7. Now from equation 1)

Area of heptagon = 10.4 +41.8+18.9+20.25 =91.35

Hope This Helped You :)