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Given, ∠A=60
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∠ABC=80
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To find ∠DPC & ∠BCQ
Now, ∠ADC=100
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[opposite angles of cyclic quadrilateral are supplementary]
∴∠PDC=80
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Similarly, ∠PCD=60
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∴∠DPC=180
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−80
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−60
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=40
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Now, ∠CBQ=100
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∠BCQ=60
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⇒∠Q=20
∘
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