Math, asked by bindiyabindu883, 3 months ago

find the area of the configuration 4x2+9y2-36=0

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Answered by Anonymous

1

Answer:

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Answered by deepikajlmhjkknacin

2

Answer:

∴ 4x²/36 + 9y² /36 =0

∴ x²/9 + y² /4=1

Here x = 3 and b = 2

∴ a > b

∴ Given equation represents ellipse symmetric about X-axis.

∴ Required area =4 (Area of the region OAB in first quadrant)

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