Question

Find the area of the field given. All the dimensions are in metres.
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Answer 1

Answer:

14,350 sq.units

Step-by-step explanation:

First let us divide this enormous shape on the basis of known shapes ok...

1. Shape of triangles AGF, EID, and CDH.

2. Shape of trapeziums EFGI and ABCH

$ar(agf) = \frac{1}{2} \times 50 \times 80 \\ = 2000sq.unit \\ar(eid) = \frac{1}{2} \times 80 \times 60 \\ = 2400sq.unit \\ ar(dch) = \frac{1}{2} \times (70 + 80) \times 35 = \\ \frac{1}{2} \times 150 \times 35 \\ = 2625sq.unit \\ \\ \\ these \: were \: for \: triangles$

for trapeziums

$ar(efig) = \frac{1}{2} \times (50 + 60) \times 60 \\ = 4400sq.unit \\ ar(abgc) = \frac{1}{2} \times (30 + 35) \times (80 + 10) \\ = \frac{1}{2} \times (30 + 35) \times 90 \\ = 2925sq.unit$

Therefore total area of ABCDEFA = ar(AGF)+ar(EID)+ar(HCD)+ar(EFIG)+ar(ABGC)

=2000+2,400+2,625+4,400+2,925

=14,350 sq.units

I hope you are clear if not just comment me and don't forgot to mark my answer as brainliest