Question

Find the area of the field in the form of a rhombus, if
the length of each side be 14 cm and the altitude be
16 cm.

​

Answer 1

Answer:

224cm2

Step-by-step explanation:

If u draw a diagonal across the two opposite vertices u get two congruent triangles each with base 14and height 16

therefore ara of rhombus = 2 x area of one triangle

= 2 x (1/2 x 14 x 16)

= 224cm2

Answer 2

$\bold {\underline {ANSWER}}$

$\bold {Given}$ => A rhombus ABCD. AB = 14cm & BD = 16cm

$\bold {To\ find}$ => Area of rhombus ABCD

Here,

Area of triangle ABD

=> 1/2 × B × H

=> 1/2 × BD × AB

=> 1/2 × 14 × 16

=> $112cm {}^{2}$

Now area of rhombus = 2 × area of triangle ABD

[ Because area of BCD = 1/2 × 16 × 14 which is same as triangle ABD. So area of rhombus = ar.(ABD + BCD)]

So area of rhombus ABCD = 2 × 112

=> $224 {cm}^{2}$

$\bold {\underline{So\ area\ of\ rhombus\ ABCD\ = 224cm^2}}$