Question

find the area of the field shown in fig 20.39 by divided into a square a rectangle and a trapezium

Answer 1

Firstly draw the lines to indicate the square,the rectangle and the trapezium
Then,
Required area=area of square+area of rectangle+area of trapezium


Area of square=side^2=4^2=4*4=16cm^2

Area of rectangle=l*b=8*4=32cm^2

Area of trapezium=1/2*(sum of parallel sides)*distance between them
=1/2*(8+3)*4=1/2*11*4=11*2=22cm^2


required area=(16+32+22)cm^2=70cm^2

Answer 2

Answer:

70 $cm^{2}$

Step-by-step explanation:

From the figure we can write,

Area of given figure = Area of square ABCD + Area of rectangle DEFG + Area of

rectangle GHIJ + Area of triangle FHI

i.e., Area of given figure = side × side + length × breadth + length × breadth + 1/2 × base

× altitude

Area of given figure = 4×4 + 8×4 + 3×4 + 1/2×5×5

Area of given figure = 16 + 32 + 12 + 10 = 70