Question

find the area of the field whose length is (3x²y+y²) and breadth is 5/8 x²​

Answer 1

Answer:

area = (3x^2y+y^2)(5/8x^2)

= 15/8x^4y+5/8x^2y^2

Answer 2

$\huge\mathfrak\red{\star{\underline{\underline{Answer}}}}$

❥ $\large\mathcal\green{Area = Length× Breadth}$

❥ $Area = (3{x}^{2}y+{y}^{2}) ×\frac{5}{8}{x}^{2}$

❥ $Area = \frac{15{x}^{4}y}{8} + \frac{5{y}^{2}{x}^{2}}{8}$

Hope it helps úh