Question

find the area of the figure where hypothenuse=53m and the base =45m.​

Answer 1

Answer:

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Answer 2

Given :-

The given figure is of triangle,

• Hypotenuse of ΔRAJ = 53 m
• Base of triangle ΔRAJ = 45 m

To Find :-

• The area of the ΔRAJ.

Solution :-

In ΔRAJ, m∠RAJ = 90°

Applying Pythagoras theorem,

⭐ RJ² = RA² + AJ²

[ Putting values ]

↪ 53² = RA² + 45²

↪ 2809 = RA² + 2025

↪ RA² = 2809 - 2025

↪ RA² = 784

↪ RA = 28 m

[ °.° RA is altitude of ΔRAJ ]

↪Altitude of ΔRAJ = 28 m

Now, we know that,

⭐ Area of ΔRAJ = ¹/2 × Base × altitude

[ Putting values ]

↪ Area of ΔRAJ = ¹/2 × 45 × 28

↪ Area of ΔRAJ = 45 × 14

↪ Area of ΔRAJ = 630 m².

Hence,

• The area of ΔRAJ is 630 m².