find the area of the following
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Step-by-step explanation:
Draw a straight line QM from Q perpendicular to RS.
Therefore, SM = PQ = 18m
Therefore, MR = (30-18)m = 12m
By Pythagorus Theorem,
(QR)^2 = (QM)^2 + (MR) ^2
=> (QM)^2 = (QR)^2 - (MR)^2
=> (QM)^2 = (15)^2 - (12)^2
=> (QM)^2 = 225 - 144
=> (QM)^2 = 81
=> QM = √81
=> QM = 9
Therefore, area of ∆QMR
= (1/2 × 12 × 9)m
= 54m^2
Therefore, area of rect. PQSM
= (18×9)m
= 162m^2
Therefore, total area of the figure,
= (54+162)m
= 216m^2
Ans.) The area of the given figure is 216m^2.
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