Find the area of the following figure
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Construction = Join A and c and then find ac by Pythagoras theorem
AB²+ BC² = AC²
5² + 12²= AC²
25+ 144 = AC²
169 = AC²
AC = 13m
Similarly, AD = 13m
Area of Δ ABC= Ar(ΔEAD) = 1/2 x 12 x 5 = 30 m²
Area of Δ ADC by heron's formula= 60 m²
Area of given figure = Ar(ΔABC)+ Ar(ΔADC) + Ar(ΔEAD) =( 30 +60 +30 )m²
Area of given figure = 120m²
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