Question

Find the area of the following polygon if ABCD and EFGH are isosceles and congruent trapezium​

Answer 1

Step-by-step explanation:

Area of rectangle + area of trapezium trapezium=area area of polygon

$area \: of \: rectangle \: is = 5 \times 28 = 140$

area of trapezium

$area \: of \: trapezium = \frac{1}{2} \times Sum \: of \: parallel \: sides × Distance \: between \: them$

$\frac{1}{2 } \times (5 + 10) \times 12 = 90$

90+140 =230cm square