Question

find the area of the following polygons​

Answer 1

Answer:

area of the polygon= area of ∆+ area of trapezium

area= 1/2×base×height+ 1/2×(sum of // sides)×h

=>1/2×12×30+1/2×(30+24)×15

=> 180+ 405

=>585cm²

Answer 2

Step-by-step explanation:

Area of polygon ABCDEA = Area of ∆ABE + Area of BEDC

Area of ∆ABE =

$\frac{1}{2} \times b \times h$

$\frac{1}{2} \times 12 \times 30 \\ = 180c {m}^{2}$

Area of trapezium =

$\frac{a + b}{2} \times h$

$\frac{30 + 24}{2} \times 15 \\ \frac{54}{2} \times 15 \\ 27 \times 15 \\ = 405c {m}^{2}$

Total area =

$180 + 405 \\ = 585c {m}^{2}$