Question

find the area of the following polygons please answer it who will give the answer fast and correct will be marked as brilliant answer​

Answer 1

Answer:

$}huge\mathfrak\red{holamate}$

Area of Ist part

Area of a triangle

base =17cm

height=9-5= 4 cm

Area of a ∆=1/2×base ×height

=1/2×17×4

=34cm sq.

Area of a rectangle

Length=5cm

breadth=17cm

area of rectangle=length×breadth

=(5×17) cm sq.

85 cm sq.

Total area

Area of ∆ + Area of rectangle

=34+85

=119cm sq.

Area of IInd part

area of ∆

Base =35 cm

height=10cm

area of ∆ = 1/2 × 35 × 10

=175 cm sq.

area of sec. ∆

base = 35 cm.

height= 10cm.

area of ∆=1/2× 35×10

=175 cm sq.

area of rectangle

Breadth = 12 cm

length = 35 cm

Area of rectangle= length × breadth

= 12×35

=420 cm.sq.

Total area

Area of both traingle + area of the rectangle

=119+420

=539 cm sq.

$\huge\mathfrak\pink{thanks}$

Answer 2

Step-by-step explanation:

check the attachment (◍•ᴗ•◍)❤