Math, asked by HarshKhtri, 1 year ago

find the area of the following quadrilaterals

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Answered by ArchitectSethRollins
110
Hi friend
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Your answer
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(a) Area of the quadrilateral = area of ∆ABC + area of ∆ADC

=> [(1/2 × 3 × 6) + (1/2 × 5 × 6)] cm²

=> [9 + 15] cm²

=> 24 cm²

(b) Area of the rhombus

=> [1/2 × 6 × 7] cm²

=> 21 cm²

(c) Area of the parallelogram = area of the two triangles

Area of two triangles in a parallelogram formed by a diagonal are equal.

So,
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Area = [2 × (1/2 × 2 × 8) ] cm²

=> [2 × 8] cm²

=> 16 cm²

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Answered by Rashiji
28
Hope its useful to you...
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