Math, asked by muthukumarperu, 10 months ago

find the area of the following right angled triangle
1)base=14m, height=17.5m
2)base=12.8cm, height= 6cm
3)base23/4, height 9/2 cm​

Answers

Answered by antareepray2
1

1)Area of the triangle

 =  \frac{1}{2}  \times 14 \times 17.5 = 122.5 {m}^{2}

2) Area of the triangle

 =  \frac{1}{2}  \times 12.8 \times 6 = 38.4 {cm}^{2}

3) Area of the triamgle

 \frac{1}{2}   \times  \frac{23}{4}  \times  \frac{9}{2}  =  \frac{207}{16}  = 12.93 {cm}^{2}

HOPE THIS COULD HELP!!!

Answered by SidVK
0

1. Area = 1/2 × b × h

= 1/2 × 14 × 17.5

= 122.5 m^2.

2. Area = 1/2 × 12.8 × 6

= 38.4 cm^2

3. Area = 1/2 × 23/4 × 9/2

= 207 / 16

= 12.938 cm^2.

●●●●●●●●●●●●●●●●●●●●

Hope it was helpful

Similar questions