find the area of the given figure
Answers
there are 1sqr and 2triangles
area of square=side×side
=6×6
36sq.cm
area of triangle=1)1/2×base×height
=1/2×2×4
=4sq.cm
2)1/2×2×4
=4sq.cm
total area=36+4+4
44sq.m. ans.
--------tnx------
Hey mate,
Here is ur answer:
In triangle SPD,
Angle SDP = 90° (given)
SD = b1
DP = h
Triangle SPD is a right angled triangle
By Pythagoras Theorem,
PD2 + SD2 = SP2
PD2 = SP2 - SD2
PD2 = (5*5) - (4*4)
PD2 = 25 - 16
PD2 = 9
PD = 3cm
Similarly,
In triangle AET,
Angle AET = 90°
ET = b1
AE = h
By Pythagoras Theorem,
AE = 3cm
In quadrilateral KPAR,
KP perpendicular and parallel to AR
KR perpendicular and parallel to PA
Thus,
Quadrilateral KPAR is a rectangle.
KR = PA = 6cm ( b2 )
KP = KD + PD ( K-D-P)
KP = 4 + 3 = 7cm
KP = AR = 7cm ( l )
Area of rectangle = 2( l+b2)
Area 1 = 2 ( 7 + 6)
Area 1 = 2*13
Area 1 = 26 sq.cm........ (i)
Area of triangles =2( 1/2*b1*h) (two congruent triangles)
Area 2 = 2 ( 1/2 * 4*3)
Area 2 = 2 (2*3)
Area 2 = 2*6
Area 2 = 12sq. cm........ (ii)
Total area = Area 1 + Area 2
Total Area = 26 + 12...... (from i and ii)
Total Area = 38sq.cm
Answer:
Total area of the given figure is 38sq.cm
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