Question

find the area of the given trapezium ​

Answer 1

Here,

given the height of tripezium = 6 cm

and the parelel sides = 14 cm and 18 cm

area of trapezium

= ½ × height × sum of parelel sides

= ½ × 6 × (14 + 18)

= 3 × 32

= 96 cm

so,

the area of the trapezium = 93 cm

Answer 2

$\large\underline{ \underline{ \sf \: Solution : \: \: \: }}$

Given ,

$\star$Height of trapezium = 6 cm

$\star$Parallel sides = 14 cm & 18 cm

We know that ,

$\sf\large \fbox{ \fbox{Area = \frac{1}{2} (sum \: of \: parallel \: sides ) \times height}}$

$\implies \sf Area = \frac{1}{2} (14 + 18) \times 6 \\ \\ \implies \sf Area = = \frac{1}{2} (32) \times 6 \\ \\ \implies \sf Area = 16 \times 6 \\ \\ \implies \sf Area = 96 \: \: {cm}^{2}$

Hence , 96 cm² is the required value