Question

The accelaration of particles various with time as: a(t)=3t²+4 if the initial velocity of particles is 2m/s.find the velocity of particles at t=3sec.​

Answer 1

Answer:

a(t)=3t^2+4

By integration we get

v(t)=t^3+4t

then put limits v=4 and t=3

then we get

v-4=3^3+4*3

v-4=9+12

v=9+12+4=25

Answer 2

a(t)=3t²+4

differentiate w.r.t (t)

6t = v

if t = 3

18 m/s = v