Question

Find the area of the isosceles triangle having base 4 cm and the lengths of one of the equal

sides is 5cm.
ans: 2√21 cm square​

Answer 1

Answer:

by using the formula

area =

$\sqrt{s(s - a)(s - b)(s - c)}$

where s = semi perimeter of the triangle

=

$\sqrt{7(7 - 5)(7 - 5)(7 - 4)}$

=

$\sqrt{7 \times 2 \times 2 \times 3}$

$2 \sqrt{21} cm$

Answer 2

Answer:

• semiperimeter =( 5+5+4 ) ÷2 = 7

1. so area of triangle=
2. $\sqrt{7(7 - 5)(7 - 5)(7 - 4) } = \sqrt{7 x2x2x3} = 2 \sqrt{21}$