Question

find the area of the major sector whose radius is 14cm and making an angle of 60°​

Answer 1

SOLUTION:-

Given:

•Radius= 14cm

•Angle = theta=60°

To find:

The area of the major sector.

Explanation:

Formula of the sector:

$= > \frac{ \theta}{360 \degree} \times \pi {r}^{2}$

So,

$= > \frac{60 \degree}{360 \degree} \times \frac{22}{7} \times 14 \times 14 \\ \\ = > \frac{1}{6} \times 22 \times 2 \times 14 \\ \\ = > \frac{616}{6} {cm}^{2} \\ \\ = > 102.66 {cm}^{2}$

Thus,

The area of the sector is 102.66cm².

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Answer 2

Answer:

Step-by-step explanation:

$\bf \underline{Given :-}$

Radius of circle, r = 14 cm

Θ = 60°

$\bf \underline{To \: Find :-}$

Area of the major sector

$\bf \underline{Formula \: to \: be \: used :-}$

$\boxed{\bf\underline{Area \: of \: sector = \frac{\theta}{360 \degree}\times\pi r^2}}$

$\bf \underline{Solution :-}$

$\sf \implies Area \: of \: sector = \frac{\theta}{360 \degree}\times\pi r^2$

$\sf \implies Area \: of \: sector =\frac{\theta}{360 \degree}\times3.14\times14\times14$

$\sf \implies Area \: of \: sector =\frac{1}{6}\times3.14\times14\times14$

$\bf \implies Area \: of \: sector =102.573 \: cm^2$

Hence, the area of the major sector is 102.573 cm².