Question

Find the area of the of the rectangle whose base is 40cm and diagonal is 41cm.​

Answer 1

Answer:

360cm^2

Step-by-step explanation:

360cm^2 is correct answer

Answer 2

Answer:

98 cm

Step-by-step explanation:

As we can see in the rectangle,

By Pythagoras theorem,

Diagonal² = (Length)² + (Width)²

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

(41)² = (40)² + (Width)²

(Width)² = (41)² - (40)²

(Width)² = 1681 - 1600

(Width)² = 81

Width = 9cm

Hence the width of the rectangle is 9 cm.

So

The perimeter of the rectangle = 2 ( Length + Width )

= 2 ( 40 cm + 9 cm )

= 2 x 49 cm

= 98 cm

Hence the perimeter of the rectangle is 98 cm.

Hope it helps you mate..