Find the area of the parallelogram ABCD (fig: 1), in which AB = 12 cm, BC = 17 cm and AC = 25 cm
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by this method you can solve your question guys
this questions answer is 15
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Answer:
30√36 sq cm²
Step-by-step explanation:
Divide parallelogram into two triangles. Name it as triangle ABC and ADC.
Triangle ABC
Sides a;12 cm b;17 cm c;25 cm
=a+b+c/2
12+17+25 cm/2 = 54/2 =27 cm
S-a=27-12=15 cm
S-b=27-17=10 cm
S-c=27-25=3 cm
√S(s-a)(s-b)(s-c)
√27-15-10-3
√3*9-15-10-3
√3*9-3*5-10-3
3√9-5-2*5
3*5√9*2
15√18 sq cm²
triangle ABC=ADC
Because parallelogram opposite sides bisect each other.
15√18 + 15√18 sq cm²
30√36 sq cm²
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