Math, asked by SSbooks16, 6 months ago

Find the area of the path if the radius of big and small circles are 15 cm and 12 cm respectively. Take (π=3.14)

Answers

Answered by khushbujha049
0

Answer:

it should be in paper wait u follow me than i will solve it

Answered by thebrainlykapil
50

Question:-

  • Find the area of the path if the radius of big and small circles are 15 cm and 12 cm respectively.

Given:-

  1. Radius of bigger circle = 15cm
  2. Radius of smaller circle = 12cm
  3. Take (π=3.14)

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\boxed{ \sf \blue{ </strong><strong>Understanding</strong><strong>\: the \: </strong><strong>Question</strong><strong>  }}

  • In this question , we have to find the Area of Path. For that, we have to find the area of bigger circle and area of smaller circle. Then we have to Minus the area of bigger circle with smaller circle.

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Let do it :-

\sf\green{ Area  \: of \: Smaller  \: Circle\:}

\begin{gathered}\begin{gathered}: \implies \underline\orange{ \boxed{\displaystyle \sf \bold\red{\: Area \: of \: Circle \: = \: \pi \: r ^{2}  }} }\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \:Area \: = \: 3.14 \: × \: (12)²\\ \\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \:Area \: = \: 3.14 \: × \: 12 \: × \: 12\\ \\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \:Area \: = \: 452.16cm\\ \\ \\\end{gathered}\end{gathered}

\boxed{ \sf \red{ Area \: of \: Smaller \: Circle \: =\:  452.16cm  }}

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\sf\green{ Area  \: of \: Bigger \: Circle\:}

\begin{gathered}\begin{gathered}: \implies \underline\orange{ \boxed{\displaystyle \sf \bold{\: Area \: of \: Circle \: = \: \pi \: r ^{2}  }} }\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \:Area \: = \: 3.14 \: × \: (15)²\\ \\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \:Area \: = \: 3.14 \: × \: 15 \: × \: 15\\ \\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \:Area \: = \: 706.5cm\\ \\ \\\end{gathered}\end{gathered}

\boxed{ \sf \red{ Area \: of \: Bigger \: Circle \: =\: 706.5cm  }}

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\sf\green{ Area  \: of \: Path\:}

\begin{gathered}\begin{gathered}: \implies \underline\orange{ \boxed{\displaystyle \sf \bold{\: Area \: of \: Path \: = \: Area  \: of \: Bigger \: one \: - \: Area \: of \: Smaller\: one  }} }\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \green\implies \displaystyle \sf \:Area \:of \: path \: = \: 706.5 \: - \: 452.16\\ \\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}: \green\implies \displaystyle \sf \:Area \:of \: path \: = \: 254.34cm\\ \\ \\\end{gathered}\end{gathered}

\boxed{ \sf \red{ Area \: of \: Path \: =\: 254.34cm  }}

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So, the area of path = 254.34cm

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