find the area of the polygon sides are in m. I will mark answer as brainliest.
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Area of triangle DES = 1/2 X base X height
= 1/2 X 18 X 20 =180
Area of triangle DRC = 1/2 X 22 X 58 = 638
Area of triangle AQF = 1/2 X 27 X 48 = 648
Area of triangle APB = 1/2 X 30 X 34 = 510
Area of parallelogram FQSE = 1/2 X sum of parallel sides X height = 1/2 X (27+18) X 52 = 1872
Area of parallelogram PBCR =
1/2 X (30+22) X 28 = 114
Now area of polygon= 180+638+648+1872+1148( cm*2 or m*2 whatever the given unit is)
= 4486 (cm*2 or m*2)
NOTE: In all the area's you should put (m*2 or cm*2) as unit was not given so kept it till numbers
HOPE IT HELPS MARK AS BRAINLIEST
= 1/2 X 18 X 20 =180
Area of triangle DRC = 1/2 X 22 X 58 = 638
Area of triangle AQF = 1/2 X 27 X 48 = 648
Area of triangle APB = 1/2 X 30 X 34 = 510
Area of parallelogram FQSE = 1/2 X sum of parallel sides X height = 1/2 X (27+18) X 52 = 1872
Area of parallelogram PBCR =
1/2 X (30+22) X 28 = 114
Now area of polygon= 180+638+648+1872+1148( cm*2 or m*2 whatever the given unit is)
= 4486 (cm*2 or m*2)
NOTE: In all the area's you should put (m*2 or cm*2) as unit was not given so kept it till numbers
HOPE IT HELPS MARK AS BRAINLIEST
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