Question

find the area of the quadrant whose circumference is 22 cm.

Answer 1

$\huge\mathbb{Heya}$

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$<b>$
Q. What is quadrant ?

A. Quadrant is the 4th part of a circle.

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$\huge\mathsf{Formulas \ :-}$

$Circumference \ of \ a \ quadrant \ = \frac{2πr}{4}$

$Area \ of \ a \ quadrant \ = \frac{πr^2}{4}$

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$\mathbb{Given \ question \ :-}$

$\textbf{Find \ the \ area \ of \ the \ quadrant}$
$\textbf{whose \ circumference \ is \ 22 \ cm.}$

$\tt\red{Answer \ :-}$
$<b>$
Circumference = 22 cm

Also, $Circumference = \frac{2πr}{4}$

So,

$\frac{2πr}{4} = 22$

$\frac{2 × 22 × r}{7 × 4} = 22$

$r = \frac{22 × 7 × 4}{22 × 2}$

r = 14 cm

Now,

$Area \ of \ quadrant \ = \frac{πr^2}{4}$

$Area \ of \ quadrant \ = \frac{22 × 14 × 14}{7 × 4}$

Area of quadrant = 154 cm².

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$\tt\red{The \ answer \ is \ 154 \ cm^2}$

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$\huge\mathfrak{Hope \ this \ helps.}$

Answer 2

Answer:

Step-by-step explanation:

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