Find the area of the quadrilateral ABCD given on the figure.
Note : please give the answer with steps.
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use area of triangle twice= 1/2×base×height
1/2×18×54+1/2×62×20
1/2×18×54+1/2×62×20
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area of quadrilateral ABCD = area of ∆ ADC + area of ∆ ABC
= 1/2 × b×h +1/2 × h× b
= 1/2 ( 54×18 + 20×62
= 1106 cm2 .
= 1/2 × b×h +1/2 × h× b
= 1/2 ( 54×18 + 20×62
= 1106 cm2 .
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