Question

Find the area of the quadrilateral ABCDhere,AC=22cm,BM=3cm,DN=3cm,andBM perpendicular AC,DN perpendicular AC

Answer 1

HERE IS YOUR SOLUTION....,

ABCD is a Rhombus.

Area of rhombus = diagonal (1)×diagonal (2)/2
= AC×BD/2
= 22×6/2
= 132/2
= 66cm^2

HOPE THIS HELPS YOU.