Question

find the area of the quadrilateral coordinates of whose vertices are 1, 2, 6, 2, 5, 3 and 3, 4​

Answer 1

area of quad.=area of triangle ABC + area of triangle ADC

ar of ABC =1/2(1*(2-3)+6*(3-2)+5(2-2))

=1/2(-1+6)

=2.5 sq unit

ar of ADC=1/2(1*(7-3)+3*(3-2)+5*(2-7))

=9sq unit

therefore 2.5+9=11.5 sq units

Answer 2

Answer:

11.5 sq units

Step-by-step explanation:

area of quadrilateral =area of triangle ABC + area of triangle ADC

area of ABC =1/2(1*(2-3)+6*(3-2)+5(2-2))

=1/2(-1+6)

=2.5 sq unit

area of ADC=1/2(1*(7-3)+3*(3-2)+5*(2-7))

=9sq unit

therefore 2.5+9=11.5 sq units