Math, asked by anushkachauhan2401, 2 months ago

find the area of the quadrilateral whose vertices, taken in order, are (-4,-2),(-3,-5),(3,-2) and (2,3)

Answers

Answered by jeevansmshetty09

0

Answer:

8.5

Step-by-step explanation:

A= 1÷2[-4(-3)-3(0)+3(0)]

A=1÷2(12)

A=6

A=1÷2[-4(-5)+3(5)+2(0)]

A=1÷2[-20+15]

A=1÷2[-5]

A=2.5

A=A'+A"

A= 8.5

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